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Answer Posted / swetcha
Method overloading occurs when a class contains two methods
with the same name, but different signatures
| Is This Answer Correct ? | 3 Yes | 0 No |
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class CTest { public: void someMethod() { int nCount = 0; cout << "This is some method --> " << nCount; } }; int main() { CTest *pctest; pctest->someMethod(); return 0; } It will executes the someMethod() and displays the value too. how is it possible with our creating memory for the class . i think iam not creating object for the class. Thanks in Advance... Prakash
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