Answer Posted / harend

results :

i=-2
j=2
k=0
m=1
First, the '&&' part is to be considered over '||'.

AS follow: m = ++i||++j&&++k (is given)
what ever be the result of (++j&&++k),the value of m =1
,since the new value i= -2 (i.e a non zero value so taken as
true or 1)
so,
1||(++j&&++k) will always be true, that is 1 . compiler
ignores ++j ,++k and only consider ++i.

thank you !

How are variables declared in c?

1151

---

What is boolean in c?

1150

---

What is the meaning of ?

1082

---

Find MAXIMUM of three distinct integers using a single C statement

1118

---

Tell me is null always defined as 0(zero)?

1136

---

i have a written test for microland please give me test pattern

2784

---

What is data structure in c programming?

1132

---

‎How to define structures? · ‎

1149

---

Is it possible to initialize a variable at the time it was declared?

1258

---

This is a variation of the call_me function in the previous question:call_me (myvar)int *myvar;{ *myvar += 5; }The correct way to call this function from main() will be a) call_me(myvar) b) call_me(*myvar) c) call_me(&myvar) d) expanded memory

1341

---

Are negative numbers true in c?

1112

---

PROGRAM TO WRITE CONTENTS OF 1 FILE IN REVERSE TO ANOTHER FILE,PROGRAM TO COPY 1 FILE TO ANOTHER BY SPECIFYING FILE NAMES AS COMMAND LINE

2088

---

string reverse using recursion

2535

---

What functions are used in dynamic memory allocation in c?

1122

---

Explain what does the characters 'r' and 'w' mean when writing programs that will make use of files?

1310

---