Answer Posted / harend

results :

i=-2
j=2
k=0
m=1
First, the '&&' part is to be considered over '||'.

AS follow: m = ++i||++j&&++k (is given)
what ever be the result of (++j&&++k),the value of m =1
,since the new value i= -2 (i.e a non zero value so taken as
true or 1)
so,
1||(++j&&++k) will always be true, that is 1 . compiler
ignores ++j ,++k and only consider ++i.

thank you !

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