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What will be the output-
for(i=1;i<=3;i++)
{
printf("%d",i);
continue;
i++;
}

Answer Posted / chetan

This will not result in a Compiler-error, because "Unreachable-code" is a warning in C, not a compilation error.

The output will be:
123

Is This Answer Correct ?    6 Yes 2 No



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