Answer Posted / adarsh

Cement =(1*1.54/(1+2+4))/0.0347
= 6.34 bag

Sand =2*(1*1.54/(1+2+4))
=0.44 Cum.

Aggregate=4*(1*1.54/(1+2+4))
=0.88 Cum.

Assume
W/C= 0.55

Water = 6.34*0.347*0.55*1000
=120.998 l.

std penetration resistance in very stiff clays lies bet 2 & 4 4 & 8 8 & 15 15 & 30

1967

---

How do you calculate the unit weight of concrete?

1075

---

i have a interlock pavement work.i need to compact about 2000 sq metres of sub base grade c of thickness 15 cm.what is the amount of water required for compaction ??

2047

---

how to prepare site mix design

1914

---

how many litres of enamel paint required for 5000 sft of site?? 

1873

---

What is the use of extruded feature in solidsworks?

1177

---

What is gravity flow?

1127

---

How to calculate the cement and fine aggregate requirement for solid block masonry works in terms of Sqm. 1. 400x200x200mm 2. 400x200x100mm 3. 600x200x100mm 4. 600x200x200mm I need the answer for 1 Sqm of solid block works.

2631

---

Special thing in designing a overhead reservoir ? which is different from an ordinary design

1164

---

Whats be the minimum foundation depth of multistoried building as per height of building in individual footing?

1826

---

What Are The Different Type Of Slump Test Indications?

1175

---

hai, kindly send anyone for output workers format details for construction project in foundation to finishing.

1466

---

What are the basic use of runners and standards of pipelines?

1168

---

need to join coaching institute in coimbatore tamilnadu ......say me the best coaching for IAS

1833

---

can any one give me sample question paper of BHEL at mdansari86@gmail.com as i m appearing for the same exam.

2100

---