There i-is initialised by 10. and j-also initialised by address of i. so

main()

{

int *j;

{

int i=10;

j=&i;

}

printf("%d",*j);

}

Question Posted / jerome.s,final year eee,adhipa

Answer Posted / jerome.s,final year eee,adhipa

There i-is initialised by 10.
and j-also initialised by address of i.
so *j is the value in the address of j.
therefore,
*j=i=10.
OUTPUT:
10

Is This Answer Correct ?

7 Yes

1 No

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