Answer Posted / arunkumar995

Function overloadig can not be achive only chaining the
return type.We must havv to change the aruments.

int add(int a,int b)
char*add(int a,int b)

one think that return type not make important role in
function overloading.In fun Overloading must effect on the
arguments.
Thus we say the given [int add(int a,int b)
char*add(int a,int b)]is not function overloaded.

What is polymorphism in oop example?

507

---

What does I oop mean?

609

---

What is the oops and benefits of oops programming?

545

---

What is polymorphism explain its types?

672

---

What is the importance of oop?

603

---

---

Why is destructor used?

574

---

class CTest { public: void someMethod() { int nCount = 0; cout << "This is some method --> " << nCount; } }; int main() { CTest *pctest; pctest->someMethod(); return 0; } It will executes the someMethod() and displays the value too. how is it possible with our creating memory for the class . i think iam not creating object for the class. Thanks in Advance... Prakash

1685

---

What is abstraction encapsulation?

647

---

What is object in oop with example?

688

---

What is this pointer in oop?

545

---

Why is abstraction needed?

559

---

What is interface in oop?

655

---

What is destructor give example?

595

---

What is the real time example of encapsulation?

586

---

Why multiple inheritance is not possible?

590

---