Answer Posted / n.kurma rao (kurmi) srkr

volume of concrete quantity is
V = L * B * H.
V = .6*.6*.16
V = .576 CUM

Dry Volume required is 35% = .778 CUM.

in that Cement is .778 * 1 /13 = .0598 CUM of Cement
Cement in terms of bags in .0598/.0347 = 1.724 bags
Sand required is .778 * 4 /13 = .239 CUM of Sand
course aggregae is .778 * 8 /13 = .479 CUM of aggregate.

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