What is the range of efficiency of thermal or steam power
plants?
Why it is so low?
Answer Posted / nitin sarda
Nice answer
| Is This Answer Correct ? | 0 Yes | 1 No |
Post New Answer View All Answers
We have drive feeding an output contactor for a 5000 hp motor @ 5kV application. The motor FLA is 629amps x 1.25% service factor = 786.25 amps The cable that we current have in place between the drive and the output contactor is 350kcmil- MV-105 (parallel cables). Per the NEC table 310.60 (C) (69). This show the cable ampacity is at 615 amps per cable for a rating of 1230 amps. We have derated the cable for the cable tray and the multiple cables application and our calculations show that after the correction factor factor we are at 922amps. 1230 amps x .75% correction factor factor = 922.5 amps. The customer is driving us to then use another safety factor of .25% off of the already derated cable. Can you please provide a longhand calculation for your solution on this application?
Briefly describe means used by electricity suppliers to influence the flow of active and reactive power in power networks (one for each type)?
How to work E.L.C.B and how to connect in circuit.
What is magneto on a gas generator. how it functions. its out put is d.c or a.c. how it can be checked for correct functioning
How many lightning arrestors to be installed on 50MX60MX10M building and is there any formular for that?
1 Ton is equal to how many watts?
what is self capacitance of inductor
how does ELR works? explain
Application Comparison between 22KV (UE)and 33KV (E) system. Are we allowed to use 33KV (E) cable in lieu of 22KV (UE) cable. What are the technical disadvantages.
Inductor and capacitor........power in one phase and ...... in it another phase.
A low wet bulb temperature indicates
What are the advantages and disadvantages of the ac motors?
why three phase capacitor takes unbalanced current in capacitor bank?
Explain with example of functional requirements of protection relay in terms reliability, selectivity, sensitivity
1)we have 1000 cfm Blower,Dia-1Mtr,Velocity of air 94 m/s 2)We have Natural Air velocity 94m/s 3If i Put Wind Mill in natural air ,speed is 94m/s Then it will generate Assume 100kw 4)If i put same wind mill across the Blower,air speed is same 94m/s now the Question is Will it generate 100 kw?