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fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
}
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Answer Posted / hemavathiarun
Hi all,
since the code is calling the same function with different
values,it's not at all possible to move to printf statement
until x becomes < 0
so only when the compiler gets the value of x as 0 the loop
will be stopped.
| Is This Answer Correct ? | 1 Yes | 0 No |
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