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my company total load is 1000kw, 415volt, all load are
inductive load. incoming powerfactor is .8. we want to
have0.95 pf connecting capacitors. so now how much rating of
capacitors we have to connect? show how?
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Answer Posted / rsundareee
your original p.f is 0.8(Tan 0.8) and you required p.f is
0.95(Tan 0.95).Required p.f = kW(Tan0.8 - Tan 0.95),when
you select the breaker rating of Capacitor bank you have to
conside the Hormonics (33%),For exambe breaker rating will
be 100A it shall be (100+33=133) 160A MCCB.
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