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9*8m slab 1:2:4 ratio use for M20 mix how much cent is
require it will become in cum but i want bags.
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Answer Posted / binubal123
Volume of Conc needed=9*8*0.01(assume)
=7.2Cum
M20 mix (1:2:4)
material
cement by vol=7.2*1/(1+2+4)
=1.028
Sand By Vol=7.2*2*1/(1+2+4){2*1.028}
=2.05
Agg By vol~4*1.028
=4.114
Cement in bag req=1.028*308.53(Cement Constant frm Practical Info for Quantity Surveyor P.T.Joglekar) =317.34Kg=317.34/50=6.36bags
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