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A 4 digit no may consist of the digits 6,2,7,5 where
none of the nos are repeated.Find the possible no of
combinations divisible by 36?
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Answer Posted / lava kumar
The multiples of 36 are 36,72,108,114,180..
the last digits are 6,2,8,4,0
The given numbers are 6,2,7,5
Therefore they are 2 cases The last digit either can be
accopied by 6 or 2 in 2c1 ways
The first 3 digits in 3! ways
Therefore the number of possible ways is 3!*2c1=12
Hope Iam rite.
| Is This Answer Correct ? | 4 Yes | 1 No |
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