A person X have a certain number of mangoes, he gave 1/2 of
total plus one mango to B, now he gave the 1/3 of remaining
plus one mango to C, he gave the 1/4 of remaining plus one
mango to D. Now he have no mango more, find how many mango
was at beginning?
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Answer Posted / paul
The answer is 9 mangoes.
let y be the total/original no. of mangoes
b be the remaining mangoes after gave to B
c be the remaining mangoes after gave to C
d be the remaining mangoes after gave to D
equations:
b = y - 0.5y - 1
= 0.5y - 1
c = b - (1/3)b - 1
= (2/3)b - 1
d = c - (1/4)c - 1
= (3/4)c - 1
but d = 0, thus,
c = 4/3
b = 7/2
y = 9 mangoes -> answer
| Is This Answer Correct ? | 4 Yes | 0 No |
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