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A number when divided by D leaves a remainder of 8 and when
divided by 3D leaves a remainder of 21 . What is the
remainder left, when twice the number is divided by 3D?
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Answer Posted / mohan chakradhar malla
Answer is 3
x%D =8 implies
p1 + (8/D)= x/D, ----1
x%3D= 21 implies
p2 + (21/3D)= x/3D ------2
x/D - x/3D =2x/3D -----3
from 1 and 2 and 3
(p1+8/D ) - (p2 + 21/3D) = 2x/3D
(p1-p2)+(3/3D)=2x/3D
hence logically remainder is 3
as ex 4/5 -1/5 always yields a remainder less than 5 with 4, 1 less than 5
| Is This Answer Correct ? | 63 Yes | 8 No |
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