Given an array of size N in which every number is between 1
and N, determine if there are any duplicates in it. You are
allowed to destroy the array if you like.
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Answer Posted / sankalan
sum all those no. say you get x
say there is a b (repeated) in place of a
so a-b = n(n+1)/2 - x=m(say)
sum the squares of those nos
say you get y
a^2-b^2 = 1/6(n+1)(2n+1)-y=n(say)
(a^-b^2)/(a-b)=a+b=m/n
to get a ((a+b)+(a-b))/2
to get b ((a+b)-(a-b))/2
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