Answer Posted / karuna

Mr Nithi U'r Wrong If it is 2^n-1
Then
2^n-1=2^n-1^n
(2^(n/2))^2-(1^(n/2))^2 [ like a^2 - b^2 ]
(2^(n/2)+1)*(2^(n/2)-1)) [ like (a+b) (a-b) ]

So factors is 2^(n/2)+1),2^(n/2)-1)
This also n is even and expect 2 .
2^n - 1 is not a prime.
n is odd and include 2 then
2^n - 1 is prime.

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