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what will be the output off the following program?
#include<stdio.h>
int main()
{
int a;
a=015+0*71+5;
printf("%d,a");
return0;
}
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Answer Posted / dhaval
the main point of answer is that the whole program will run
without a single damn error as it ignores %d (called the
conversion character) and just print "a" as text.
so the answer will be a.
if we write the printf statement as printf ("%d",a); in this
case it shall print the answer as 18. dont know why it
prints 18. am on my way to discover this problem out. i will
post a new answer if at all i shall find an answer to this query
regards,
Dhaval. (L.j college of computer applications.)
| Is This Answer Correct ? | 2 Yes | 2 No |
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