4 thieves rob a bakery of the breadone after the other.each
thief takes half of what is present ,& half a bread...if
at the end 3 bread remains,what is the no of bread that
was present initially?
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Answer Posted / r jain
at the end,total no of breads=3.
Let the no of breads in the bakery before 4th thief robbed
the bakery and after 3rd thief robbed=x.
Then x-(x/2+1/2)=3
=> x=7
similarly,no of breads in the bakery before 3rd thief ,2nd
thief and 1st thief robbed are 15,31 and 63 respectively.
So, total no of breads initially=No of breads before 1st
thief robbed=63.
| Is This Answer Correct ? | 4 Yes | 2 No |
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