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4 thieves rob a bakery of the breadone after the other.each
thief takes half of what is present ,& half a bread...if
at the end 3 bread remains,what is the no of bread that
was present initially?
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Answer Posted / abida hasan
soln:
no of breads initially=x
breads taken by first thief= x/2+1/2=(x+1)/2
remaining breads= x-((x+1)/2)=(x-1)/2
breads taken by second theif= ((x-1)/4)+1/2=(x+1)/4
remaining breads= x-((x+1)/4)=(x-1)/4
similarly,
remaining bread after third theif rob=(x-1)/8
remaining bread after forth theif rob=(x-1)/16
therefore,
(x-1)/16=3
x-1=48
x=49
| Is This Answer Correct ? | 2 Yes | 9 No |
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