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What will be the output-
for(i=1;i<=3;i++)
{
printf("%d",i);
continue;
i++;
}
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Answer Posted / gourab
the o/p will be 123
bcz after printing 1 for d first time then continue will
take to the for statement.thus i will take value 3.and i++
after d continue statement will never get executed,but it
will not give an error.
| Is This Answer Correct ? | 32 Yes | 2 No |
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