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In a mixture, R is 2 parts and S is 1 part. In order to
make S to 25% of the mixture, how much of R is to be added?
explain how can i solve it??
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Answer Posted / brijrat
suppose mix=x
r:s=2:1
than
r=2x/3 and s=x/3
acc. to question
let part lost by s is y to become 25% of mix
x/3-y=25x/100=x/4
y=x/3-x/4
=x/12
hence r is to be added
=((x/12)/x)*100 % of mixture=8.33%
| Is This Answer Correct ? | 10 Yes | 4 No |
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