main()

{

signed int bit=512, i=5;

for(;i;i--)

{

printf("%d\n", bit >> (i - (i -1)));

}

}

a. 512, 256, 0, 0, 0

b. 256, 256, 0, 0, 0

c. 512, 512, 512, 512, 512

d. 256, 256, 256, 256, 256

Answer Posted / shanker

Query : When bits cant be changed, then option c is also
correct?

Is This Answer Correct ?    3 Yes 0 No



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