Answer Posted / satheesh

The above answer is also wrong and Ist answer i
correct.Since the bulb is rated for 230 V and the power is
200W only at rated voltage.So the resistance is constant for
this rating.v2/w=230^2/200=264.5 ohms.If we apply 115 V also
this resistance will not vary.So the current drawn at this
time is v/R=I=115/264.5=0.435A=So definitely power = V*I
115*.435=50 Watts.

delta motor winding resistance I take normally single winding is 2.5, which value is came delta connection ie RY ?

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sir plz send some previous year questions of jspl.

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