#include<stdio.h>
main()
{
int a=1;
int b=0;
b=++a + ++a;
printf("%d %d",a,b);
}
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Answer Posted / aditya gupta
Let me make this more clear... infact if the case is of
pre-increment:
1- find all the variables of pre-increment, and compute them
2- do the assignment.
for example, what I do:
main()
{
int a=1; // initialization
int b=0; // initialization
b=++a + ++a; // find the pre-increment i.e. 2 increments of
'a' so now 'a' in this step will be incremented by 2 so now
'a' will contain 1+2=3. so now a=3. Again before assignment
compute 'a+a' which is '3+3'=6
printf("%d %d",a,b); //3 6
}
Just a trick:- always compute the pre-increments in the same
step...
If I say b= ++a + ++a; answer is 3 and 6
If I say b= ++a + a++; answer is 3 and 4 because in this
line one pre-increment is there. So now '++a + a++'= "2 + 2"
Thanks!!
Aditya Gupta
| Is This Answer Correct ? | 8 Yes | 2 No |
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