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How to create index-by table in oracle?

Answer Posted / su

declare
TYPE tab IS TABLE OF varchar2(200)
INDEX BY binary_integer;
t tab;
v_counter number : =0;
BEGIN
FOR c_emp IN (SELECT ENAME FROM emp)
LOOP
v_counter := v_counter + 1;
t(v_counter):= c_emp.ename;
END LOOP;
FOR i IN 1 .. t.last
LOOP
dbms_output.put_line(t(i));
END LOOP;
EXCEPTION
WHEN others THEN
dbms_output.put_line(sqlcode);
dbms_output.put_line(sqlerrm);
END;

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