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255.255.255.128/what is the n/w id ,broadcast id and the
number of valid host(according to disco rules)
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Answer Posted / venkatrajesh
255.255.255.128
i.e,X.X.X.X/25
HOST bits(X / XXXXXXX)
1 7
2^1 = 2 Subnets
2^7-2=126 hosts/Subnet
1st subnet 0-127
2nd subnet 128-255
N/W ip-0,128.
B/C ip-127,255.
numberof valid host-126/subnet(252hosts)
For EXAMPLE
192.168.1.0/25
192.168.1.0- 1st N/W IP
192.168.1.1-First Valid Host
192.168.1.126-Last Valid Host
192.168.1.127-B/C IP
Total no of valid host in first subnet is 126
192.168.1.128- 2nd N/W IP
192.168.1.129-First Valid Host
192.168.1.254-Last Valid Host
192.168.1.255-B/C IP
Total no of valid host in second subnet is 126
| Is This Answer Correct ? | 3 Yes | 0 No |
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