Answer Posted / debashree

In the above example one never knows how many lines are required to be print. So, to keep the program generic , we can implement it the following way:

public class FormattedOutput2 {

/**
* @param args
*/
public static void main(String[] args) {
printOutput(Integer.parseInt(args[0]), 1, 0);
}

private static void printOutput(int lastNum, int i, int num) {
int count = 0;
while(num < lastNum){
StringBuffer formatString = new StringBuffer();
while(count < i && num < lastNum){
formatString.append(++num + " ");
count++;
}
System.out.println(formatString);
i++;
count = 0;
}

}

}


Output for : 10
1
2 3
4 5 6
7 8 9 10

Output for: 102
1
2 3
4 5 6
7 8 9 10
11 12 13 14 15
16 17 18 19 20 21
22 23 24 25 26 27 28
29 30 31 32 33 34 35 36
37 38 39 40 41 42 43 44 45
46 47 48 49 50 51 52 53 54 55
56 57 58 59 60 61 62 63 64 65 66
67 68 69 70 71 72 73 74 75 76 77 78
79 80 81 82 83 84 85 86 87 88 89 90 91
92 93 94 95 96 97 98 99 100 101 102

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