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to remove the repeated numbers from the given .
i.e..,
if the input is 12233
output should of
123
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Answer Posted / sujai cn
#include <iostream>
#include <math.h>
#include<conio.h>
using namespace std;
void main()
{
int num = 0;
int ReverseNumber(int num);
int RemoveDuplicateDigits(int num);
int ReverseOfInput = 0;
cout<<"Please enter the number\n";
cin >> num;
ReverseOfInput = ReverseNumber(num);
cout<<"The number after removing duplicate digits is "
<< ReverseNumber(RemoveDuplicateDigits(ReverseOfInput)) ;
getch();
}
int ReverseNumber(int num)
{
int revnum = num;
int nodigits = 0;
int rem = 0;
while(revnum > 0)
{
nodigits ++;
revnum = revnum / 10;
}
revnum = 0;
nodigits --;
while(num > 0)
{
rem = num % 10 ;
revnum = revnum + rem * (int) (pow (10 ,nodigits));
nodigits --;
num = num / 10;
}
return revnum;
}
int RemoveDuplicateDigits(int num)
{
int resnum = 0;
bool digis[10] = {false , false ,false ,
false ,false , false ,false , false , false , false};
int power = 0;
int rem = 0;
while (num > 0)
{
rem = num % 10 ;
if(digis[rem] == false)
{
resnum = (int)(resnum + rem * pow(10 , power));
power++;
digis[rem] = true;
}
num = num / 10 ;
}
return resnum;
}
| Is This Answer Correct ? | 1 Yes | 0 No |
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