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int i;
i=2;
i++;
if(i=4)
{
printf(i=4);
}
else
{
printf(i=3);
}
output of the program ?
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Answer Posted / stuti
This program will give error. Becoz the format of if
statement and printf statement- both are wrong.
In if, instead of if(i==4), if(i=4) is written and in
printf statement, there should be printf("i==4"); and printf
("i=3");
So it will not be compiled.
| Is This Answer Correct ? | 4 Yes | 2 No |
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