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You have an int array with n elements and a structure with
three int members.
ie
struct No
{
unsigned int no1;
unsigned int no2;
unsigned int no3;
};
Point1.Lets say 1 byte in the array element is represented
like this - 1st 3 bits from LSB is one number, next 2 bits
are 2nd no and last 3 bits are 3rd no.
Now write a function, struct No* ExtractNos(unsigned int *,
int count)
which extracts each byte from array and converts LSByte in
the order mentioned in point1.and save it the structure
no1, no2, no3.
in the function struct No* ExtractNos(unsigned int *, int
count), first parameter points to the base address of array
and second parameter says the no of
elements in the array.
For example: if your array LSB is Hex F7 then result no1 =
7, no2 = 2, no3 = 7. In the same way convert all the
elements from the array and save the result in array of
structure.
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Answer Posted / vadivel t
Hi small mistake.
change the
printf("ELEMENT IN THE STRUCTURE \n", (i+1));
to
printf("ELEMENT IN THE STRUCTURE %d\n", (i+1));
| Is This Answer Correct ? | 0 Yes | 2 No |
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