Answer Posted / pradeep

Dear frd,

char a[20];
a="Hello Orcale Test";

Here you are trying to "assign" constant char string to
address variable , as you are aware that name of an array
points to the first address of the array element. So here
you wil get an error message saying L value is required.

and also
char *a;
*a="hello" ; also will give an error as you are trying to
assign constant characters to char type variable.
Type mismatch will occur.

so I suggest you to use the strcpy method to copy a
constant character string to char*

so soln is
char a[20];
strcpy(a,"hello world");

or char *a;
a="hello";

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