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The matrix of a (7,9)was given.The address of the first byte
of a (1,1)matrix=1258.It takes 4 bytes to store the
number,then calculate the address of the last byte of a
(5,8) matrix??
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Answer Posted / nash
1434
STARTING ADDRESS IS 1258.
EACH ELEMENT IS OF 4 BYTES.
SO (5,8)=44 I.E. POSITION OF ELEMENT
44*4=176
1258+176=1434
DO REPLY.
| Is This Answer Correct ? | 24 Yes | 10 No |
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