Answer Posted / amrander singh
Real Power = (Apparant Power).(Power Factor)
Here Apparantm Power = 45KVA,
Now Generally P.F = .8
Therefore Real Power = (45).(0.8) = 36KW
Hence Full Load Capacity is 36 KW
| Is This Answer Correct ? | 7 Yes | 0 No |
Post New Answer View All Answers
what is the disadvantages of common earthing for AC and DC equipment? (i am talking about inverter control room and inverter duty transformer earthing is common...?)
how much allowable resistance that can be difference in motor all coils?
what is upper impedance and lower impedance of a distance relay
hi , i have 150 kw loud and we need 50 m cabil,i want to know wich size cabil we use. thanks
Is there a diode made that works with AC 120 volt 20 amp? If so can it completely stop all current flow in 1 direction at all times?
how can service sitting be setted for MCCB?Example for sittings IR (CURRENT RATING),IS(CURRENT STARTING)IO (current operating)?
i need of the bhel question papers along with answers and also give some website names for the downloading question (electrical and electronics engg question)please help me....
How to calculate loses in transformer of 160 KVA ?
How we can recongnise the phase displacement of transformer connection between primary & scondary...plzzz explain it with example.........
Can any body tell me the different types of LT cables & their application.
What is difference between start imitation and start interlock for 3 phase motor protection ?
Which device of PlC does share load between DG sets when DG are running in perallel?
How good are you in resolving the commercial issues to Employer's advantage?
As an electrical engineer what are the responsibilities which i can hold in TCS?
What are root loci?