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A 3 digit number is such that it's unit digit is equal to
the product of the other two digits which are prime. Also,
the difference between it's reverse and itself is 396.
What is the sum of the three digits?
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Answer Posted / vignesh1988i
the number is : x*1+y*10+z*100 (236)
second eq: (z*1+y*10+x*100)-(x*1+y*10+z*100)=396 ,
solving this we get x-z=4
given that z&y are prime so it can only take 2,3,5,7 oly.
putting this trial we can solve and we will end up in
236....
thank u
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