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For testing 33kv cable hipot testing. How much kv we have to
Apply .Give in details.
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Answer Posted / s.jeganath
(2E+1)1.414=dc
2E+1 =AC
(2*33000+1)1.414=DC
67000*1.414=DC
94738v=DC (it is a 100%)
but apply in 80% only it is standard for 33kv cable
APPly voltage dc=94738*0.8=75790V
(75.790KV DC)
| Is This Answer Correct ? | 43 Yes | 18 No |
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