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Given an array of characters which form a sentence of
words, give an efficient algorithm to reverse the order of
the words (not characters) in it.

Answer Posted / patrck

//check this program....

#include <string.h>
#include <stdio.h>
main(){
char a[100],b[100];
int i,j=0,c=0,k,cnt=0;
printf("enter the sentence\n");
for(i=0;i>=0;i++){
a[i]=getchar();
if(a[i]=='\n')break;
}
for(i=0;a[i]!='\n';i++)
cnt++;
for(i=0;i<(cnt+1);i++)
b[i]=' ';
for(i=0;i<(cnt+1);i++){
c++;
if((a[i]==' ')||(a[i]=='\n')){
c=c-1;
for(j=(cnt-i),k=(i-c);c>0;k++,j++,c--){
b[j]=a[k];
}c=0;
}
}
printf("result: ");
for(i=0;i<cnt+1;i++)
putchar(b[i]); printf("\n");
}

Is This Answer Correct ?    10 Yes 1 No



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