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pointer_variable=(typecasting
datatype*)malloc(sizeof(datatype));
This is the syntax for malloc?Please explain this,how it
work with an example?
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Answer Posted / pramod
I'll add few more lines to answer above just to make it a
bit more understandable.
Malloc allocates consequetive blocks of memory of requested
size.Then it returns the starting address of this block ,
the address returned is of type void , since it is a void
pointer so we need to typecast it to one that we requested
so typecasting is done( This headache has been removed in
C++ by using new as new automatically does this typecasting)
| Is This Answer Correct ? | 2 Yes | 0 No |
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