Answer Posted / khanijkumar

for jack
3=v*t; if his speed is v and time taken was t hours
For Jill
3=u*(x+t);

There fore
v*t=u(x+t)
2*u*t=u(x+t)
2t=x+t;
x=t;
In down word direction
jill speed 3km/hr
time taken by him to cover 3 kms is 1 hr;
time taken by Jack is 3 hr;
There fore jill wait 2 hr;
x=2;

There fore t=2;
v=3/2=1.5km/hr


There fore velocity of Jack is 1.5km/hr in the upword
direction
downward velocity is 1 km/hr

there fore
average speed is 2*1.5*1/(1.5+1)=1.2km/hr

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