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a watch showed 5 minutes past 3'o clock on the sunday
evening when the correct time was 3'0 clock . it looses
uniformly and was observed to be lo min fast at 6pm.on the
next day .when did the watch show the correct time
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Answer Posted / p praveen
The time travelled by wrong clock is 27.25hrs in 27hrs.
So Speed of wrong clock is 27.25/27.
Let 'x' hrs be the number of hrs after which it shows the
correct time.
Speed of wrong clock at the correct time=distance
travelled/speed=(x+5/60)/x=27.25/27
Which implies that x=9hrs
Therefore watch showed the correct time at 3+9=12:00 AM
| Is This Answer Correct ? | 3 Yes | 2 No |
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