Write an implementation of “float stringToFloat(char *str).”
The code should be simple, and not require more than the
basic operators (if, for, math operators, etc.).
• Assumptions
• Don’t worry about overflow or underflow
• Stop at the 1st invalid character and return the number
you have converted till then, if the 1st character is
invalid return 0
• Don’t worry about exponential (e.g. 1e10), instead you
should treat ‘e’ as an invalid character
• Write it like real code, e.g. do error checking
• Go though the string only once
• Examples
• “1.23” should return 1.23
• “1a” should return 1
• “a”should return 0
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Answer Posted / nikita
#include<stdio.h>
#include<string.h>
int main()
{
int i = 0;
float result = 0;
int dec_count = 0;
int isDec = 0;
char* str = "123.76bg";
while(str[i])
{
if(str[i] == '.')
{
isDec = 1;
i++;
}
if((str[i]>=48) && (str[i]<=57))
{
result = result * 10;
result = result + (str[i++] - '0');
}
else
{
break;
}
if(isDec == 1)
{
dec_count++;
}
}
printf("\nThe result is: %f", result);
for(i=0; i<dec_count; i++)
{
result = result / 10;
}
printf("\nThe result is: %f", result);
return 0;
}
| Is This Answer Correct ? | 1 Yes | 2 No |
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