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Answer Posted / rabid manatee
#include <iostream>
using namespace std;
int main(int argc, char *argv[]) {
int n = 4;
if (argc == 2) {
n = atoi(argv[1]);
}
for(int i=n; i >= 0; i--) {
cout << i*2 + 1 <<endl;
}
}
| Is This Answer Correct ? | 3 Yes | 14 No |
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