Answer Posted / rishabh agrawal

A1 - Dangling pointer points to a memory location which is
being removed.
E.g.
int* a = new int;
int *b = a;
delete b;

Now a will be a dandling pointer.

A2 - Memory leaks occur when memory allocated to a pointer
is not deleted and the pointer goes out of scope. This
allocated memory never gets de-allocated and remains in the
heap until the system is restarted.
E.g.
void foo()
{
int* ptr = new int;
*ptr = 10;
...
...
}
Since ptr is allocated memory using 'new', but no 'delete'
is called, hence memory allocated to ptr will leak.

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1179

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how can i access a direct (absolute, not the offset) memory address? here is what i tried: wrote a program that ask's for an address from the user, creates a FAR pointer to that adress and shows it. then the user can increment/decrement the value in that address by pressing p(inc+) and m(dec-). NOW, i compiled that program and opened it twice (in 2 different windows) and gave twice the same address to it. now look what happen - if i change the value in one "window" of the program, it DOES NOT change in the other! even if they point to the same address in the memory! here is the code snippet: //------------------------------------------------------ #include //INCLUDE EVERY KNOWN HEADER FILE #include //FOR ANY CASE... #include #include #include main() { int far *ptr; //FAR POINTER!!! long address; char key=0; //A KEY FROM THE KEYBOARD int temp=0; clrscr(); cout<<"Enter Address:"; cin>>hex>>address; //GETS THE ADDRESS clrscr(); (long)ptr=address; temp=*ptr; //PUTS THE ADDRESS IN THE PTR cout<<"["<

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