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find a number whether it is even or odd without using any
control structures and relational operators?

Answer Posted / vignesh1988i

THE LAST two answers posted by two folks are correct but the
declarations have been made wrong...... we cant make use of
1D array here , if so only 'e' or 'o' only will get
printed.... but that is not our aim... so correct
declaration is using a 2D array.....
char a[][6]={{"even"},{"odd"}};

and also it is not the must to make use of array of pointers
concept...........

thank u

Is This Answer Correct ?    3 Yes 2 No



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