find a number whether it is even or odd without using any
control structures and relational operators?
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Answer Posted / vignesh1988i
THE LAST two answers posted by two folks are correct but the
declarations have been made wrong...... we cant make use of
1D array here , if so only 'e' or 'o' only will get
printed.... but that is not our aim... so correct
declaration is using a 2D array.....
char a[][6]={{"even"},{"odd"}};
and also it is not the must to make use of array of pointers
concept...........
thank u
| Is This Answer Correct ? | 3 Yes | 2 No |
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