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find a number whether it is even or odd without using any
control structures and relational operators?
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Answer Posted / vinocit
#include<stdio.h>
int main()
{
int n=10000;
char *s[2]={"Even","Odd"};
printf("%s",s[n&1]);
return 0;
}
| Is This Answer Correct ? | 47 Yes | 11 No |
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