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Cost of an item is x. It's value increases by p% and
decreases by p% Now the new value is 1 rupee, what is the
actual value ?
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Answer Posted / phaniram
Let the item cost be I then,
Item cost by increasing p% will be:
I(100+p)/100
Item Cost by decreasing p% will be:
I(100+p)(100-p)/100*100
But the above is equal to 1.
So,
I(100^2-p^2)/100^2 = 1 => I = 100^2/(100^2 - p^2).
| Is This Answer Correct ? | 25 Yes | 9 No |
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