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write the function. if all the character in string B appear in
string A, return true, otherwise return false.

Answer Posted / satish nerlekar

//assuming both the strings in same case

int main()
{

string A;
string B;

int count = 0;
char repeatChar='$';

cout<<"Enter string A";
cin>>A;
cout<<"Enter the string B";
cin>>B;

if(A.length()<B.length())
{
cout<<"Length of string A is small than B, so all the charaters of the B can't be there in A";
exit(0);
}


int A_length = A.length();
int B_length = B.length();

for(int i=0; i<B_length; i++)
{
for(int j=0; j<A_length; j++)
{
if(A[j] == B[i])
{
if(repeatChar == A[j])
;
else
{
count++;
repeatChar = A[j];
break;
}

}
}
}

if(count==B_length)
cout<<"string A has all the chars of string B";
else
cout<<"string A doesn't have all chars of string B";

return 0;

}

Is This Answer Correct ?    1 Yes 0 No



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