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fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
}
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Answer Posted / mahesh patil
Only answer 1
answer 4
answer 7 are correct others are wrong..
If you are confident on your answers please check once then
write a post.
Correct Answer: 0 1 2 5 10
This will print in reverse order because, This is a
recursive call, Every time a function is called the values
are stored in stack/stack is created. when x value reaches
0 then it will return. So stack is LIFO order, So it will
print the values in reverse order.
| Is This Answer Correct ? | 9 Yes | 0 No |
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we called a function and passed something do it we have always passed the "values" of variables to the called function. such functions calles are called a) calls by reference b) calls by value c) calls by zero d) none of the above
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