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Write an implementation of “float stringToFloat(char *str).”
The code should be simple, and not require more than the
basic operators (if, for, math operators, etc.).
• Assumptions
• Don’t worry about overflow or underflow
• Stop at the 1st invalid character and return the number
you have converted till then, if the 1st character is
invalid return 0
• Don’t worry about exponential (e.g. 1e10), instead you
should treat ‘e’ as an invalid character
• Write it like real code, e.g. do error checking
• Go though the string only once
• Examples
• “1.23” should return 1.23
• “1a” should return 1
• “a”should return 0
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Answer Posted / piyush sharma
float stringToFloat(char *str)
{
char ch;
int decimal_pt = 0;
int dec_count = 0;
float val = 0.0;
for( int i=0; str[i]!='\0'; i++ )
{
ch = str[i];
if( ch == '.' )
{
decimal_pt = 1;
continue;
}
if( !(ch>=48 && ch<=57) )
break;
val = val*10 + ch-48;
if( decimal_pt == 1 )
dec_count++;
}
for( int i=0; i<dec_count; i++ )
val = val/10;
return val;
}
| Is This Answer Correct ? | 2 Yes | 2 No |
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