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int arr[] = {1,2,3,4}
int *ptr=arr;
*(arr+3) = *++ptr + *ptr++;
Final contents of arr[]
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Answer Posted / vijaisankar
In this statement
first ptr holds base address of the array(4000),
then as per precedence operators ptr gets post incremented
(4002)though it points the value 1(4000)(ptr is post
incremented) and then ptr gets preincrement so (4004) the
value in that one is 3 then 3+1=4.
*(arr+3)=3;
| Is This Answer Correct ? | 2 Yes | 7 No |
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