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Questions / { ernest kalulu }
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Answers / { ernest kalulu }
Question { 8345 }
Q. calculate the value of the resistor to be connected in series with a 100W;
230V lamp so that the wattage of the lamp is reduced to 35W
Answer
when resistor R is connected in series with the lamp.
lamp power=35W
lamp Voltage= 230V /* since 230v is the operating voltage of the lamp*/
series current = 35/230
=0.152 A
power dissipated at a resistor = 100 W -35 W
= 65 W
= Isqr X R
R= 65/(0.152sqr)
= 2.8 kilo-ohm
| Is This Answer Correct ? | 0 Yes | 0 No |
